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X^2-5X+30=180
We move all terms to the left:
X^2-5X+30-(180)=0
We add all the numbers together, and all the variables
X^2-5X-150=0
a = 1; b = -5; c = -150;
Δ = b2-4ac
Δ = -52-4·1·(-150)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*1}=\frac{-20}{2} =-10 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*1}=\frac{30}{2} =15 $
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